Distance between Laxmangarh and Pop House
Distance between Laxmangarh and Pop House is 231.89 km. This distance is equal to 144.09 miles, and 125.13 nautical miles.
The distance line on map shows distance from Laxmangarh to Pop House between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between Laxmangarh to Pop House,
It takes 0.26 hours to arrive.
| Laxmangarh | 27.822549 | 75.028014 |
|---|---|---|
| Pop House | 28.5229778 | 77.2565103 |
| Distance | 231.89 km | 144.09 miles |
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