Distance between Kaluga and Alexandrov, Vladimir Oblast
Distance between Kaluga and Alexandrov, Vladimir Oblast is 258.03 km. This distance is equal to 160.33 miles, and 139.23 nautical miles.
The distance line on map shows distance from Kaluga to Alexandrov, Vladimir Oblast between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between Kaluga to Alexandrov, Vladimir Oblast,
It takes 0.29 hours to arrive.
| Kaluga | 54.5333333 | 36.2666667 |
|---|---|---|
| Alexandrov, Vladimir Oblast | 56.3947309 | 38.712037 |
| Distance | 258.03 km | 160.33 miles |
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