Distance between Johannesburg and Siyabuswa-F
Distance between Johannesburg and Siyabuswa-F is 159 km. This distance is equal to 98.8 miles, and 85.79 nautical miles.
The distance line on map shows distance from Johannesburg to Siyabuswa-F between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between Johannesburg to Siyabuswa-F,
It takes 0.18 hours to arrive.
| Johannesburg | -26.2041028 | 28.0473051 |
|---|---|---|
| Siyabuswa-F | -25.108197 | 29.066357 |
| Distance | 159 km | 98.8 miles |
Related Distances
- Distance between Johannesburg and Pretoria (55,28 km.)
- Distance between Johannesburg and Siyabuswa-F (159,00 km.)
- Distance between Johannesburg and Standerton (145,54 km.)
- Distance between Johannesburg and Mabopane (78,36 km.)
- Distance between Johannesburg and Wolmaransstad (235,26 km.)
- Distance between Johannesburg and Modimolle (171,08 km.)