Distance between Jacksonville and Seminole County
Distance between Jacksonville and Seminole County is 185.16 km. This distance is equal to 115.05 miles, and 99.91 nautical miles.
The distance line on map shows distance from Jacksonville to Seminole County between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between Jacksonville to Seminole County,
It takes 0.21 hours to arrive.
| Jacksonville | 30.3321838 | -81.655651 |
|---|---|---|
| Seminole County | 28.7131688 | -81.2078164 |
| Distance | 185.16 km | 115.05 miles |
Related Distances
- Distance between Jacksonville and Lakeside (24,95 km.)
- Distance between Jacksonville and Saint Johns (29,71 km.)
- Distance between Orlando and Jacksonville (201,24 km.)
- Distance between Jacksonville and Savannah (201,78 km.)
- Distance between Jacksonville and Yonaomi Circle (204,56 km.)
- Distance between Jacksonville and Gulf (360,84 km.)