Distance between Jacksonville and Sanford
Distance between Jacksonville and Sanford is 178.4 km. This distance is equal to 110.85 miles, and 96.27 nautical miles.
The distance line on map shows distance from Jacksonville to Sanford between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between Jacksonville to Sanford,
It takes 0.2 hours to arrive.
| Jacksonville | 30.3321838 | -81.655651 |
|---|---|---|
| Sanford | 28.7588218 | -81.2941794 |
| Distance | 178.4 km | 110.85 miles |
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