Distance between Giaginskaya and selo Aleksandrovskoye
Distance between Giaginskaya and selo Aleksandrovskoye is 233.39 km. This distance is equal to 145.02 miles, and 125.94 nautical miles.
The distance line on map shows distance from Giaginskaya to selo Aleksandrovskoye between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between Giaginskaya to selo Aleksandrovskoye,
It takes 0.26 hours to arrive.
| Giaginskaya | 44.8694306 | 40.0660211 |
|---|---|---|
| selo Aleksandrovskoye | 44.7163697 | 43.0161592 |
| Distance | 233.39 km | 145.02 miles |
Related Distances
- Distance between Giaginskaya and Pashkovskiy (78,37 km.)
- Distance between Giaginskaya and Bryukhovetskaya (132,76 km.)
- Distance between Giaginskaya and Kamchatka (192,84 km.)
- Distance between Giaginskaya and Zelenokumsk (306,12 km.)
- Distance between Giaginskaya and Chegem (316,25 km.)
- Distance between Giaginskaya and Bilohirs'k (430,27 km.)