Distance between Dzerzhinsky and Alexandrov, Vladimir Oblast
Distance between Dzerzhinsky and Alexandrov, Vladimir Oblast is 100.19 km. This distance is equal to 62.25 miles, and 54.06 nautical miles.
The distance line on map shows distance from Dzerzhinsky to Alexandrov, Vladimir Oblast between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between Dzerzhinsky to Alexandrov, Vladimir Oblast,
It takes 0.11 hours to arrive.
| Dzerzhinsky | 55.6333333 | 37.85 |
|---|---|---|
| Alexandrov, Vladimir Oblast | 56.3947309 | 38.712037 |
| Distance | 100.19 km | 62.25 miles |
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