Distance between Columbus School of Law and Savage
Distance between Columbus School of Law and Savage is 27.49 km. This distance is equal to 17.08 miles, and 14.83 nautical miles.
The distance line on map shows distance from Columbus School of Law to Savage between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between Columbus School of Law to Savage,
It takes 0.03 hours to arrive.
| Columbus School of Law | 38.9360434 | -76.9975622 |
|---|---|---|
| Savage | 39.1436111 | -76.8247222 |
| Distance | 27.49 km | 17.08 miles |
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