Distance between Clifton and Sayreville Junction
Distance between Clifton and Sayreville Junction is 45.91 km. This distance is equal to 28.53 miles, and 24.77 nautical miles.
The distance line on map shows distance from Clifton to Sayreville Junction between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between Clifton to Sayreville Junction,
It takes 0.05 hours to arrive.
| Clifton | 40.8584328 | -74.1637553 |
|---|---|---|
| Sayreville Junction | 40.4653838 | -74.3304256 |
| Distance | 45.91 km | 28.53 miles |
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