Distance between Badin and Sevierville
Distance between Badin and Sevierville is 315.62 km. This distance is equal to 196.12 miles, and 170.31 nautical miles.
The distance line on map shows distance from Badin to Sevierville between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between Badin to Sevierville,
It takes 0.35 hours to arrive.
| Badin | 35.4047222 | -80.1158333 |
|---|---|---|
| Sevierville | 35.8681455 | -83.561835 |
| Distance | 315.62 km | 196.12 miles |
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