Distance between Araranguá and São Leopoldo
Distance between Araranguá and São Leopoldo is 185.22 km. This distance is equal to 115.09 miles, and 99.94 nautical miles.
The distance line on map shows distance from Araranguá to São Leopoldo between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between Araranguá to São Leopoldo,
It takes 0.21 hours to arrive.
| Araranguá | -28.9356371 | -49.4863711 |
|---|---|---|
| São Leopoldo | -29.7549941 | -51.150283 |
| Distance | 185.22 km | 115.09 miles |
Related Distances
- Distance between Araranguá and Viamão (195,65 km.)
- Distance between Araranguá and São Joaquim (83,71 km.)
- Distance between Araranguá and São Sebastião do Caí (196,89 km.)
- Distance between Araranguá and Rosário do Sul (545,05 km.)
- Distance between Araranguá and Tijucas (206,18 km.)
- Distance between Araranguá and Joaçaba (278,21 km.)