Distance between Alexandrov and Chekhov
Distance between Alexandrov and Chekhov is 159.39 km. This distance is equal to 99.04 miles, and 86.01 nautical miles.
The distance line on map shows distance from Alexandrov to Chekhov between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between Alexandrov to Chekhov,
It takes 0.18 hours to arrive.
| Alexandrov | 56.4 | 38.7166667 |
|---|---|---|
| Chekhov | 55.1526207 | 37.4604756 |
| Distance | 159.39 km | 99.04 miles |
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