Distance between Alexandrov, Vladimir Oblast and Semyonov
Distance between Alexandrov, Vladimir Oblast and Semyonov is 357.04 km. This distance is equal to 221.85 miles, and 192.66 nautical miles.
The distance line on map shows distance from Alexandrov, Vladimir Oblast to Semyonov between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between Alexandrov, Vladimir Oblast to Semyonov,
It takes 0.4 hours to arrive.
| Alexandrov, Vladimir Oblast | 56.3947309 | 38.712037 |
|---|---|---|
| Semyonov | 56.8 | 44.5 |
| Distance | 357.04 km | 221.85 miles |
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