Distance between Alexandrov, Vladimir Oblast and Pereslavl'-Zalesskiy
Distance between Alexandrov, Vladimir Oblast and Pereslavl'-Zalesskiy is 40.67 km. This distance is equal to 25.27 miles, and 21.94 nautical miles.
The distance line on map shows distance from Alexandrov, Vladimir Oblast to Pereslavl'-Zalesskiy between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between Alexandrov, Vladimir Oblast to Pereslavl'-Zalesskiy,
It takes 0.05 hours to arrive.
| Alexandrov, Vladimir Oblast | 56.3947309 | 38.712037 |
|---|---|---|
| Pereslavl'-Zalesskiy | 56.747048 | 38.8902603 |
| Distance | 40.67 km | 25.27 miles |
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