Distance between Alexandrov, Vladimir Oblast and Orekhovo-Zuyevo
Distance between Alexandrov, Vladimir Oblast and Orekhovo-Zuyevo is 67.99 km. This distance is equal to 42.25 miles, and 36.69 nautical miles.
The distance line on map shows distance from Alexandrov, Vladimir Oblast to Orekhovo-Zuyevo between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between Alexandrov, Vladimir Oblast to Orekhovo-Zuyevo,
It takes 0.08 hours to arrive.
| Alexandrov, Vladimir Oblast | 56.3947309 | 38.712037 |
|---|---|---|
| Orekhovo-Zuyevo | 55.8 | 38.966667 |
| Distance | 67.99 km | 42.25 miles |
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