Distance between Alexandrov, Vladimir Oblast and Kineshma
Distance between Alexandrov, Vladimir Oblast and Kineshma is 237.58 km. This distance is equal to 147.62 miles, and 128.2 nautical miles.
The distance line on map shows distance from Alexandrov, Vladimir Oblast to Kineshma between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between Alexandrov, Vladimir Oblast to Kineshma,
It takes 0.26 hours to arrive.
| Alexandrov, Vladimir Oblast | 56.3947309 | 38.712037 |
|---|---|---|
| Kineshma | 57.433333 | 42.133333 |
| Distance | 237.58 km | 147.62 miles |
Related Distances
- Distance between Korolyov and Alexandrov, Vladimir Oblast (76,81 km.)
- Distance between Tutayev and Alexandrov, Vladimir Oblast (173,06 km.)
- Distance between poselok Sofrino and Alexandrov, Vladimir Oblast (56,24 km.)
- Distance between Shatura and Alexandrov, Vladimir Oblast (104,71 km.)
- Distance between Alexandrov, Vladimir Oblast and Chekhov (158,74 km.)
- Distance between Gavrilov-Yam and Alexandrov, Vladimir Oblast (122,72 km.)