Distance between Alexandrov, Vladimir Oblast and Kashin
Distance between Alexandrov, Vladimir Oblast and Kashin is 126.16 km. This distance is equal to 78.39 miles, and 68.08 nautical miles.
The distance line on map shows distance from Alexandrov, Vladimir Oblast to Kashin between two cities.
If you travel with an airplane (which has average speed of 560 miles per hour) between Alexandrov, Vladimir Oblast to Kashin,
It takes 0.14 hours to arrive.
| Alexandrov, Vladimir Oblast | 56.3947309 | 38.712037 |
|---|---|---|
| Kashin | 57.3568441 | 37.6111844 |
| Distance | 126.16 km | 78.39 miles |
Related Distances
- Distance between Rublevo V Krylatskom and Alexandrov, Vladimir Oblast (107,71 km.)
- Distance between Skhodnya and Alexandrov, Vladimir Oblast (100,42 km.)
- Distance between Staraya Kupavna and Alexandrov, Vladimir Oblast (73,81 km.)
- Distance between Zelenograd and Alexandrov, Vladimir Oblast (105,06 km.)
- Distance between Lobnya and Alexandrov, Vladimir Oblast (86,84 km.)
- Distance between Alexandrov, Vladimir Oblast and Semyonov (357,04 km.)