Distance from Swidwin to Aleksandrow Lodzki
Distance from Świdwin to Aleksandrów Łódzki is 322 kilometers. This air travel distance is equal to 200 miles.
The air travel (bird fly) shortest distance between Świdwin and Aleksandrów Łódzki is 322 km or 200 miles.
If you travel with an airplane (which has average speed of 560 miles) from Swidwin to Aleksandrow Lodzki, It takes 0.36 hours to arrive.
Swidwin
Swidwin is located in Poland.
| GPS Coordinates (DMS) | 53° 46´ 28.7040'' N 15° 46´ 36.1560'' E |
|---|---|
| Latitude | 53.77464 |
| Longitude | 15.77671 |
| Altitude | 92 m |
| Country | Poland |
Świdwin Distances to Cities
| Świdwin | Distance |
|---|---|
| Distance from Swidwin to Swidnica | 330 km |
| Distance from Swidwin to Olesnica | 305 km |
| Distance from Swidwin to Inowroclaw | 198 km |
| Distance from Swidwin to Sopot | 197 km |
| Distance from Swidwin to Poznan | 171 km |
Aleksandrow Lodzki
Aleksandrow Lodzki is located in Poland.
| GPS Coordinates | 51° 49´ 10.7400'' N 19° 18´ 13.8240'' E |
|---|---|
| Latitude | 51.81965 |
| Longitude | 19.30384 |
| Altitude | 195 m |
| Country | Poland |