Distance from Zelenodolsk to Pleasure Ridge Park
Distance from Zelenodolsk to Pleasure Ridge Park is 8,733 kilometers. This air travel distance is equal to 5,426 miles.
The air travel (bird fly) shortest distance between Zelenodolsk and Pleasure Ridge Park is 8,733 km= 5,426 miles.
If you travel with an airplane (which has average speed of 560 miles) from Zelenodolsk to Pleasure Ridge Park, It takes 9.69 hours to arrive.
Zelenodolsk
Zelenodolsk is located in Russia.
| GPS Coordinates (DMS) | 55° 50´ 37.5360'' N 48° 31´ 4.2240'' E |
|---|---|
| Latitude | 55.84376 |
| Longitude | 48.51784 |
| Altitude | 104 m |
| Country | Russia |
Zelenodolsk Distances to Cities
| Zelenodolsk | Distance |
|---|---|
| Distance from Zelenodolsk to Brownwood | 9,826 km |
| Distance from Zelenodolsk to Biloxi | 9,632 km |
| Distance from Zelenodolsk to Melville | 7,983 km |
| Distance from Zelenodolsk to Kokomo | 8,505 km |
| Distance from Zelenodolsk to Montrose | 9,316 km |
Pleasure Ridge Park
Pleasure Ridge Park is located in United States.
| GPS Coordinates | 38° 8´ 43.2600'' N 85° 51´ 29.8800'' W |
|---|---|
| Latitude | 38.14535 |
| Longitude | -85.85830 |
| Altitude | 139 m |
| Country | United States |