Distance from to

Distance from Winona to San Angelo

Distance from Winona to San Angelo is 1,595 kilometers. This air travel distance is equal to 991 miles.

The air travel (bird fly) shortest distance between Winona and San Angelo is 1,595 km= 991 miles.

If you travel with an airplane (which has average speed of 560 miles) from Winona to San Angelo, It takes 1.77 hours to arrive.

Winona

Winona is located in United States.

GPS Coordinates (DMS)44° 2´ 59.8560'' N
91° 38´ 21.5520'' W
Latitude44.04996
Longitude-91.63932
Altitude202 m
CountryUnited States

Winona Distances to Cities

WinonaDistance
Distance from Winona to Sioux Falls411 km
Distance from Winona to Brookings413 km
Distance from Winona to Fargo511 km
Distance from Winona to Milwaukee322 km
Distance from Winona to Neenah255 km

San Angelo

San Angelo is located in United States.

GPS Coordinates31° 27´ 49.5720'' N
100° 26´ 13.3440'' W
Latitude31.46377
Longitude-100.43704
Altitude564 m
CountryUnited States

San Angelo Distances to Cities

San AngeloDistance
Distance from San Angelo to Eagle1,948 km
Distance from San Angelo to West Odessa200 km
Distance from San Angelo to Moscow2,210 km
Distance from San Angelo to Albany Or2,455 km
Distance from San Angelo to Twin Falls1,749 km