Distance from West Virginia to Seymour
Distance from West Virginia to Seymour is 702 kilometers. This air travel distance is equal to 436 miles.
The air travel (bird fly) shortest distance between West Virginia and Seymour is 702 km= 436 miles.
If you travel with an airplane (which has average speed of 560 miles) from West Virginia to Seymour, It takes 0.78 hours to arrive.
West Virginia
West Virginia is located in United States.
| GPS Coordinates (DMS) | 38° 35´ 51.4680'' N 80° 27´ 17.6400'' W |
|---|---|
| Latitude | 38.59763 |
| Longitude | -80.45490 |
| Altitude | 590 m |
| Country | United States |
West Virginia Distances to Cities
| West Virginia | Distance |
|---|---|
| Distance from West Virginia to Kentucky | 345 km |
| Distance from West Virginia to Ohio | 292 km |
| Distance from West Virginia to California | 3,417 km |
| Distance from West Virginia to New York | 601 km |
| Distance from West Virginia to Pennsylvania | 402 km |
Seymour
Seymour is located in United States.
| GPS Coordinates | 41° 23´ 48.3360'' N 73° 4´ 33.3840'' W |
|---|---|
| Latitude | 41.39676 |
| Longitude | -73.07594 |
| Altitude | 30 m |
| Country | United States |
Seymour Distances to Cities
| Seymour | Distance |
|---|---|
| Distance from Seymour Ct to Torrance | 4,036 km |
| Distance from Seymour Ct to Orange Ca | 3,998 km |
| Distance from Seymour Ct to Cambridge | 196 km |
| Distance from Seymour Ct to Albany Ca | 4,186 km |
| Distance from Seymour Ct to Bedford Nh | 215 km |