Distance from Veruela to San Fernando
Distance from Veruela to San Fernando is 1,126 kilometers. This air travel distance is equal to 700 miles.
The air travel (bird fly) shortest distance between Veruela and San Fernando is 1,126 km= 700 miles.
If you travel with an airplane (which has average speed of 560 miles) from Veruela to San Fernando, It takes 1.25 hours to arrive.
Veruela
Veruela is located in Philippines.
| GPS Coordinates (DMS) | 8° 4´ 23.1600'' N 125° 57´ 20.8800'' E |
|---|---|
| Latitude | 8.07310 |
| Longitude | 125.95580 |
| Altitude | 31 m |
| Country | Philippines |
Veruela Distances to Cities
| Veruela | Distance |
|---|---|
| Distance from Veruela to Manila | 904 km |
| Distance from Veruela to Ipil | 373 km |
| Distance from Veruela to Monkayo | 31 km |
| Distance from Veruela to Cebu City | 336 km |
| Distance from Veruela to Cagayan De Oro | 151 km |
San Fernando
San Fernando is located in Philippines.
| GPS Coordinates | 16° 36´ 57.2760'' N 120° 18´ 59.8680'' E |
|---|---|
| Latitude | 16.61591 |
| Longitude | 120.31663 |
| Altitude | 9 m |
| Country | Philippines |