Distance from Shamkir Rayon to Monrovia
Distance from Şǝmkir to Monrovia is 6,793 kilometers. This air travel distance is equal to 4,221 miles.
The air travel (bird fly) shortest distance between Şǝmkir and Monrovia is 6,793 km= 4,221 miles.
If you travel with an airplane (which has average speed of 560 miles) from Shamkir Rayon to Monrovia, It takes 7.54 hours to arrive.
Shamkir Rayon
Shamkir Rayon is located in Azerbaijan.
| GPS Coordinates (DMS) | 40° 49´ 48.3600'' N 46° 1´ 21.6480'' E |
|---|---|
| Latitude | 40.83010 |
| Longitude | 46.02268 |
| Altitude | 455 m |
| Country | Azerbaijan |
Şǝmkir Distances to Cities
| Şǝmkir | Distance |
|---|---|
| Distance from Shamkir Rayon to Monrovia | 6,793 km |
| Distance from Shamkir Rayon to Montserrado | 6,752 km |