Distance from to

Distance from Seymour to Waukegan

Distance from Seymour to Waukegan is 1,229 kilometers. This air travel distance is equal to 764 miles.

The air travel (bird fly) shortest distance between Seymour and Waukegan is 1,229 km= 764 miles.

If you travel with an airplane (which has average speed of 560 miles) from Seymour to Waukegan, It takes 1.36 hours to arrive.

Seymour

Seymour is located in United States.

GPS Coordinates (DMS)41° 23´ 48.3360'' N
73° 4´ 33.3840'' W
Latitude41.39676
Longitude-73.07594
Altitude30 m
CountryUnited States

Seymour Distances to Cities

SeymourDistance
Distance from Seymour Ct to Torrance4,036 km
Distance from Seymour Ct to Orange Ca3,998 km
Distance from Seymour Ct to Cambridge196 km
Distance from Seymour Ct to Bedford Nh215 km
Distance from Seymour Ct to Albany Ca4,186 km

Waukegan

Waukegan is located in United States.

GPS Coordinates42° 21´ 49.0680'' N
87° 50´ 41.2440'' W
Latitude42.36363
Longitude-87.84479
Altitude199 m
CountryUnited States

Waukegan Distances to Cities

WaukeganDistance
Distance from Waukegan to Waukesha79 km
Distance from Waukegan to Appleton216 km
Distance from Waukegan to Toledo364 km
Distance from Waukegan to Pittsburgh690 km
Distance from Waukegan to West Chicago61 km