Distance from Seoni to Ozamiz City
Distance from Seonī to Ozamiz City is 4,982 kilometers. This air travel distance is equal to 3,096 miles.
The air travel (bird fly) shortest distance between Seonī and Ozamiz City is 4,982 km= 3,096 miles.
If you travel with an airplane (which has average speed of 560 miles) from Seoni to Ozamiz City, It takes 5.53 hours to arrive.
Seoni
Seoni is located in India.
| GPS Coordinates (DMS) | 22° 5´ 11.9040'' N 79° 33´ 1.5480'' E |
|---|---|
| Latitude | 22.08664 |
| Longitude | 79.55043 |
| Altitude | 628 m |
| Country | India |
Seonī Distances to Cities
| Seonī | Distance |
|---|---|
| Distance from Seoni to Candaba | 4,411 km |
| Distance from Seoni to Ozamiz City | 4,982 km |
Ozamiz City
Ozamiz City is located in Philippines.
| GPS Coordinates | 8° 8´ 53.1600'' N 123° 50´ 25.8000'' E |
|---|---|
| Latitude | 8.14810 |
| Longitude | 123.84050 |
| Altitude | 10 m |
| Country | Philippines |