Distance from to

Distance from Savage to Lake Oswego

Distance from Savage to Lake Oswego is 2,297 kilometers. This air travel distance is equal to 1,427 miles.

The air travel (bird fly) shortest distance between Savage and Lake Oswego is 2,297 km= 1,427 miles.

If you travel with an airplane (which has average speed of 560 miles) from Savage to Lake Oswego, It takes 2.55 hours to arrive.

Savage

Savage is located in United States.

GPS Coordinates (DMS)44° 46´ 44.8680'' N
93° 20´ 10.8240'' W
Latitude44.77913
Longitude-93.33634
Altitude216 m
CountryUnited States

Savage Distances to Cities

SavageDistance
Distance from Savage to Wooster1,031 km
Distance from Savage to Rye1,656 km
Distance from Savage to Lyndhurst1,628 km
Distance from Savage to Bismarck621 km
Distance from Savage to Colonia1,624 km

Lake Oswego

Lake Oswego is located in United States.

GPS Coordinates45° 25´ 14.4120'' N
122° 40´ 14.3400'' W
Latitude45.42067
Longitude-122.67065
Altitude61 m
CountryUnited States

Lake Oswego Distances to Cities

Lake OswegoDistance
Distance from Lake Oswego to Newberg27 km
Distance from Lake Oswego to Tigard8 km
Distance from Lake Oswego to Tualatin8 km
Distance from Lake Oswego to Seattle244 km
Distance from Lake Oswego to Milwaukie4 km