Distance from Sandila to Wilmington Island
Distance from Sandīla to Wilmington Island is 13,180 kilometers. This air travel distance is equal to 8,190 miles.
The air travel (bird fly) shortest distance between Sandīla and Wilmington Island is 13,180 km= 8,190 miles.
If you travel with an airplane (which has average speed of 560 miles) from Sandila to Wilmington Island, It takes 14.62 hours to arrive.
Sandila
Sandila is located in India.
| GPS Coordinates (DMS) | 27° 4´ 13.5120'' N 80° 30´ 52.5600'' E |
|---|---|
| Latitude | 27.07042 |
| Longitude | 80.51460 |
| Altitude | 137 m |
| Country | India |
Sandīla Distances to Cities
| Sandīla | Distance |
|---|---|
| Distance from Sandila to Wilmington Island | 13,180 km |
| Distance from Sandila to Rowlett | 13,359 km |
| Distance from Sandila to Chattanooga | 12,970 km |
| Distance from Sandila to Layton | 12,353 km |
| Distance from Sandila to Pleasanton | 12,469 km |
Wilmington Island
Wilmington Island is located in United States.
| GPS Coordinates | 32° 0´ 12.7800'' N 80° 58´ 25.3920'' W |
|---|---|
| Latitude | 32.00355 |
| Longitude | -80.97372 |
| Altitude | 11 m |
| Country | United States |