Distance from Sakhalin to Frisco
Distance from Sakhalin to Frisco is 9,030 kilometers. This air travel distance is equal to 5,611 miles.
The air travel (bird fly) shortest distance between Sakhalin and Frisco is 9,030 km= 5,611 miles.
If you travel with an airplane (which has average speed of 560 miles) from Sakhalin to Frisco, It takes 10.02 hours to arrive.
Sakhalin
Sakhalin is located in Russia.
| GPS Coordinates (DMS) | 50° 41´ 27.5280'' N 142° 57´ 2.0520'' E |
|---|---|
| Latitude | 50.69098 |
| Longitude | 142.95057 |
| Altitude | 399 m |
| Country | Russia |
Sakhalin Distances to Cities
| Sakhalin | Distance |
|---|---|
| Distance from Sakhalin to Frisco | 9,030 km |
| Distance from Sakhalin to Cupertino | 7,229 km |
| Distance from Sakhalin to California | 7,433 km |
| Distance from Sakhalin to Ridgewood | 9,229 km |
| Distance from Sakhalin to Avocado Heights | 7,745 km |
Frisco
Frisco is located in United States.
| GPS Coordinates | 33° 9´ 2.4120'' N 96° 49´ 24.9960'' W |
|---|---|
| Latitude | 33.15067 |
| Longitude | -96.82361 |
| Altitude | 216 m |
| Country | United States |