Distance from to

Distance from Romulus to San Leandro

Distance from Romulus to San Leandro is 3,319 kilometers. This air travel distance is equal to 2,062 miles.

The air travel (bird fly) shortest distance between Romulus and San Leandro is 3,319 km= 2,062 miles.

If you travel with an airplane (which has average speed of 560 miles) from Romulus to San Leandro, It takes 3.68 hours to arrive.

Romulus

Romulus is located in United States.

GPS Coordinates (DMS)42° 13´ 20.1360'' N
83° 23´ 47.7600'' W
Latitude42.22226
Longitude-83.39660
Altitude203 m
CountryUnited States

Romulus Distances to Cities

RomulusDistance
Distance from Romulus to Ithaca569 km
Distance from Romulus to Southfield31 km
Distance from Romulus to Minneapolis853 km
Distance from Romulus to Elmira545 km
Distance from Romulus to North Tonawanda383 km

San Leandro

San Leandro is located in United States.

GPS Coordinates37° 43´ 29.7480'' N
122° 9´ 21.8880'' W
Latitude37.72493
Longitude-122.15608
Altitude19 m
CountryUnited States

San Leandro Distances to Cities

San LeandroDistance
Distance from San Leandro to Santa Rosa93 km
Distance from San Leandro to San Ramon17 km
Distance from San Leandro to South Lake Tahoe232 km
Distance from San Leandro to Santa Cruz84 km
Distance from San Leandro to Sunnyvale41 km