Distance from Portoviejo to Seminole
Distance from Portoviejo to Seminole is 3,207 kilometers. This air travel distance is equal to 1,993 miles.
The air travel (bird fly) shortest distance between Portoviejo and Seminole is 3,207 km= 1,993 miles.
If you travel with an airplane (which has average speed of 560 miles) from Portoviejo to Seminole, It takes 3.56 hours to arrive.
Portoviejo
Portoviejo is located in Ecuador.
| GPS Coordinates (DMS) | 1° 3´ 16.4880'' S 80° 27´ 16.0200'' W |
|---|---|
| Latitude | -1.05458 |
| Longitude | -80.45445 |
| Altitude | 44 m |
| Country | Ecuador |
Portoviejo Distances to Cities
| Portoviejo | Distance |
|---|---|
| Distance from Portoviejo to Prospect Heights | 4,838 km |
| Distance from Portoviejo to Bothell | 6,750 km |
| Distance from Portoviejo to Savage | 5,235 km |
| Distance from Portoviejo to Castro Valley | 6,056 km |
| Distance from Portoviejo to Pinole | 6,092 km |
Seminole
Seminole is located in United States.
| GPS Coordinates | 27° 50´ 23.1000'' N 82° 47´ 28.3560'' W |
|---|---|
| Latitude | 27.83975 |
| Longitude | -82.79121 |
| Altitude | 16 m |
| Country | United States |