Distance from Popovo to Jacksonville Beach
Distance from Popovo to Jacksonville Beach is 9,028 kilometers. This air travel distance is equal to 5,610 miles.
The air travel (bird fly) shortest distance between Popovo and Jacksonville Beach is 9,028 km= 5,610 miles.
If you travel with an airplane (which has average speed of 560 miles) from Popovo to Jacksonville Beach, It takes 10.02 hours to arrive.
Popovo
Popovo is located in Bulgaria.
| GPS Coordinates (DMS) | 43° 21´ 0.0000'' N 26° 13´ 59.9880'' E |
|---|---|
| Latitude | 43.35000 |
| Longitude | 26.23333 |
| Altitude | 190 m |
| Country | Bulgaria |
Popovo Distances to Cities
| Popovo | Distance |
|---|---|
| Distance from Popovo to Jacksonville Beach | 9,028 km |
| Distance from Popovo to Parole | 8,040 km |
| Distance from Popovo to Owasso | 9,426 km |
| Distance from Popovo to Avenel | 7,778 km |
| Distance from Popovo to Bayonet Point | 9,272 km |
Jacksonville Beach
Jacksonville Beach is located in United States.
| GPS Coordinates | 30° 17´ 40.8840'' N 81° 23´ 35.3040'' W |
|---|---|
| Latitude | 30.29469 |
| Longitude | -81.39314 |
| Altitude | 3 m |
| Country | United States |