Distance from Ohio to San Angelo
Distance from Ohio to San Angelo is 1,863 kilometers. This air travel distance is equal to 1,158 miles.
The air travel (bird fly) shortest distance between Ohio and San Angelo is 1,863 km= 1,158 miles.
If you travel with an airplane (which has average speed of 560 miles) from Ohio to San Angelo, It takes 2.07 hours to arrive.
Ohio
Ohio is located in United States.
| GPS Coordinates (DMS) | 40° 25´ 2.2440'' N 82° 54´ 25.6320'' W |
|---|---|
| Latitude | 40.41729 |
| Longitude | -82.90712 |
| Altitude | 301 m |
| Country | United States |
Ohio Distances to Cities
| Ohio | Distance |
|---|---|
| Distance from Ohio to California | 3,183 km |
| Distance from Ohio to Pennsylvania | 490 km |
| Distance from Ohio to Chicago | 429 km |
| Distance from Ohio to Virginia | 496 km |
| Distance from Ohio to Kentucky | 310 km |
San Angelo
San Angelo is located in United States.
| GPS Coordinates | 31° 27´ 49.5720'' N 100° 26´ 13.3440'' W |
|---|---|
| Latitude | 31.46377 |
| Longitude | -100.43704 |
| Altitude | 564 m |
| Country | United States |
San Angelo Distances to Cities
| San Angelo | Distance |
|---|---|
| Distance from San Angelo to Eagle | 1,948 km |
| Distance from San Angelo to West Odessa | 200 km |
| Distance from San Angelo to Moscow | 2,210 km |
| Distance from San Angelo to Twin Falls | 1,749 km |
| Distance from San Angelo to Albany Or | 2,455 km |