Distance from Nova Kakhovka to Searcy
Distance from Nova Kakhovka to Searcy is 9,399 kilometers. This air travel distance is equal to 5,840 miles.
The air travel (bird fly) shortest distance between Nova Kakhovka and Searcy is 9,399 km= 5,840 miles.
If you travel with an airplane (which has average speed of 560 miles) from Nova Kakhovka to Searcy, It takes 10.43 hours to arrive.
Nova Kakhovka
Nova Kakhovka is located in Ukraine.
| GPS Coordinates (DMS) | 46° 45´ 16.2360'' N 33° 20´ 55.1040'' E |
|---|---|
| Latitude | 46.75451 |
| Longitude | 33.34864 |
| Altitude | 15 m |
| Country | Ukraine |
Nova Kakhovka Distances to Cities
| Nova Kakhovka | Distance |
|---|---|
| Distance from Nova Kakhovka to Searcy | 9,399 km |
| Distance from Nova Kakhovka to Boardman | 8,302 km |
| Distance from Nova Kakhovka to Redwood City | 10,362 km |
| Distance from Nova Kakhovka to Central Falls | 7,705 km |
| Distance from Nova Kakhovka to Pittsburgh | 8,315 km |
Searcy
Searcy is located in United States.
| GPS Coordinates | 35° 15´ 2.3040'' N 91° 44´ 10.5000'' W |
|---|---|
| Latitude | 35.25064 |
| Longitude | -91.73625 |
| Altitude | 82 m |
| Country | United States |