Distance from North Dakota to Sayreville Junction
Distance from North Dakota to Sayreville Junction is 2,266 kilometers. This air travel distance is equal to 1,408 miles.
The air travel (bird fly) shortest distance between North Dakota and Sayreville Junction is 2,266 km= 1,408 miles.
If you travel with an airplane (which has average speed of 560 miles) from North Dakota to Sayreville Junction, It takes 2.51 hours to arrive.
North Dakota
North Dakota is located in United States.
| GPS Coordinates (DMS) | 47° 33´ 5.3640'' N 101° 0´ 7.2360'' W |
|---|---|
| Latitude | 47.55149 |
| Longitude | -101.00201 |
| Altitude | 567 m |
| Country | United States |
North Dakota Distances to Cities
| North Dakota | Distance |
|---|---|
| Distance from North Dakota to Pennsylvania | 2,014 km |
| Distance from North Dakota to South Dakota | 407 km |
| Distance from North Dakota to Washington | 2,159 km |
| Distance from North Dakota to Virginia | 2,142 km |
| Distance from North Dakota to Oregon | 1,574 km |
Sayreville Junction
Sayreville Junction is located in United States.
| GPS Coordinates | 40° 27´ 55.3680'' N 74° 19´ 49.5480'' W |
|---|---|
| Latitude | 40.46538 |
| Longitude | -74.33043 |
| Altitude | 35 m |
| Country | United States |