Distance from North Dakota to San Angelo
Distance from North Dakota to San Angelo is 1,787 kilometers. This air travel distance is equal to 1,110 miles.
The air travel (bird fly) shortest distance between North Dakota and San Angelo is 1,787 km= 1,110 miles.
If you travel with an airplane (which has average speed of 560 miles) from North Dakota to San Angelo, It takes 1.98 hours to arrive.
North Dakota
North Dakota is located in United States.
| GPS Coordinates (DMS) | 47° 33´ 5.3640'' N 101° 0´ 7.2360'' W |
|---|---|
| Latitude | 47.55149 |
| Longitude | -101.00201 |
| Altitude | 567 m |
| Country | United States |
North Dakota Distances to Cities
| North Dakota | Distance |
|---|---|
| Distance from North Dakota to Pennsylvania | 2,014 km |
| Distance from North Dakota to South Dakota | 407 km |
| Distance from North Dakota to Washington | 2,159 km |
| Distance from North Dakota to Virginia | 2,142 km |
| Distance from North Dakota to Oregon | 1,574 km |
San Angelo
San Angelo is located in United States.
| GPS Coordinates | 31° 27´ 49.5720'' N 100° 26´ 13.3440'' W |
|---|---|
| Latitude | 31.46377 |
| Longitude | -100.43704 |
| Altitude | 564 m |
| Country | United States |
San Angelo Distances to Cities
| San Angelo | Distance |
|---|---|
| Distance from San Angelo to Eagle | 1,948 km |
| Distance from San Angelo to West Odessa | 200 km |
| Distance from San Angelo to Moscow | 2,210 km |
| Distance from San Angelo to Twin Falls | 1,749 km |
| Distance from San Angelo to Albany Or | 2,455 km |