Distance from New York to Belgrade
Distance from New York to Belgrade is 7,281 kilometers. This air travel distance is equal to 4,524 miles.
The air travel (bird fly) shortest distance between New York and Belgrade is 7,281 km= 4,524 miles.
If you travel with an airplane (which has average speed of 560 miles) from New York to Belgrade, It takes 8.08 hours to arrive.
New York
New York is located in United States.
| GPS Coordinates (DMS) | 40° 42´ 46.0080'' N 74° 0´ 21.3840'' W |
|---|---|
| Latitude | 40.71278 |
| Longitude | -74.00594 |
| Altitude | 10 m |
| Country | United States |
New York Distances to Cities
| New York | Distance |
|---|---|
| Distance from New York to Belgrade | 7,281 km |
Belgrade
Belgrade is located in Serbia.
| GPS Coordinates | 44° 48´ 14.4360'' N 20° 27´ 54.4680'' E |
|---|---|
| Latitude | 44.80401 |
| Longitude | 20.46513 |
| Altitude | 120 m |
| Country | Serbia |
Belgrade Distances to Cities
| Belgrade | Distance |
|---|---|
| Distance from Belgrade to South Lake Tahoe | 9,922 km |
| Distance from Belgrade to Missoula | 8,914 km |
| Distance from Belgrade to Pasco | 9,167 km |
| Distance from Belgrade to Weatherford | 9,398 km |
| Distance from Belgrade to Addison | 8,062 km |