Distance from Mariahu to Ozamiz City
Distance from Mariāhū to Ozamiz City is 4,772 kilometers. This air travel distance is equal to 2,965 miles.
The air travel (bird fly) shortest distance between Mariāhū and Ozamiz City is 4,772 km= 2,965 miles.
If you travel with an airplane (which has average speed of 560 miles) from Mariahu to Ozamiz City, It takes 5.29 hours to arrive.
Mariahu
Mariahu is located in India.
| GPS Coordinates (DMS) | 25° 36´ 0.1080'' N 82° 36´ 6.7320'' E |
|---|---|
| Latitude | 25.60003 |
| Longitude | 82.60187 |
| Altitude | 91 m |
| Country | India |
Mariāhū Distances to Cities
| Mariāhū | Distance |
|---|---|
| Distance from Mariahu to Ozamiz City | 4,772 km |
| Distance from Mariahu to Lubao | 4,125 km |
| Distance from Mariahu to Monkayo | 5,004 km |
| Distance from Mariahu to Atimonan | 4,296 km |
| Distance from Mariahu to Antipolo | 4,197 km |
Ozamiz City
Ozamiz City is located in Philippines.
| GPS Coordinates | 8° 8´ 53.1600'' N 123° 50´ 25.8000'' E |
|---|---|
| Latitude | 8.14810 |
| Longitude | 123.84050 |
| Altitude | 10 m |
| Country | Philippines |