Distance from Lombardy to Senago
Distance from Lombardy to Senago is 57 kilometers. This air travel distance is equal to 35 miles.
The air travel (bird fly) shortest distance between Lombardy and Senago is 57 km= 35 miles.
If you travel with an airplane (which has average speed of 560 miles) from Lombardy to Senago, It takes 0.06 hours to arrive.
Lombardy
Lombardy is located in Italy.
| GPS Coordinates (DMS) | 45° 28´ 44.6520'' N 9° 50´ 42.8640'' E |
|---|---|
| Latitude | 45.47907 |
| Longitude | 9.84524 |
| Altitude | 110 m |
| Country | Italy |
Lombardy Distances to Cities
| Lombardy | Distance |
|---|---|
| Distance from Lombardy to Bologna | 161 km |
| Distance from Lombardy to Rome | 453 km |
| Distance from Lombardy to Florence | 219 km |
| Distance from Lombardy to Venice | 195 km |
| Distance from Lombardy to Ascoli Piceno | 419 km |
Senago
Senago is located in Italy.
| GPS Coordinates | 45° 34´ 32.2320'' N 9° 7´ 34.3200'' E |
|---|---|
| Latitude | 45.57562 |
| Longitude | 9.12620 |
| Altitude | 167 m |
| Country | Italy |
Senago Distances to Cities
| Senago | Distance |
|---|---|
| Distance from Senago to Cesena | 294 km |
| Distance from Senago to Domodossola | 88 km |
| Distance from Senago to Rimini | 320 km |
| Distance from Senago to Oderzo | 264 km |
| Distance from Senago to Capannori | 224 km |