Distance from Jefferson City to Teaneck
Distance from Jefferson City to Teaneck is 1,575 kilometers. This air travel distance is equal to 979 miles.
The air travel (bird fly) shortest distance between Jefferson City and Teaneck is 1,575 km= 979 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jefferson City to Teaneck, It takes 1.75 hours to arrive.
Jefferson City
Jefferson City is located in United States.
| GPS Coordinates (DMS) | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
|---|---|
| Latitude | 38.57670 |
| Longitude | -92.17352 |
| Altitude | 195 m |
| Country | United States |
Jefferson City Distances to Cities
| Jefferson City | Distance |
|---|---|
| Distance from Jefferson City to Sacramento | 2,544 km |
| Distance from Jefferson City to Boston | 1,834 km |
| Distance from Jefferson City to San Francisco | 2,640 km |
| Distance from Jefferson City to Los Angeles | 2,386 km |
| Distance from Jefferson City to Dallas | 767 km |
Teaneck
Teaneck is located in United States.
| GPS Coordinates | 40° 53´ 51.3600'' N 74° 0´ 57.4920'' W |
|---|---|
| Latitude | 40.89760 |
| Longitude | -74.01597 |
| Altitude | 42 m |
| Country | United States |
Teaneck Distances to Cities
| Teaneck | Distance |
|---|---|
| Distance from Teaneck to Merrick | 47 km |
| Distance from Teaneck to State College | 324 km |
| Distance from Teaneck to West New York | 12 km |
| Distance from Teaneck to Islip | 70 km |
| Distance from Teaneck to Seaside | 4,133 km |