Distance from Jefferson City to Seven Oaks
Distance from Jefferson City to Seven Oaks is 1,109 kilometers. This air travel distance is equal to 689 miles.
The air travel (bird fly) shortest distance between Jefferson City and Seven Oaks is 1,109 km= 689 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jefferson City to Seven Oaks, It takes 1.23 hours to arrive.
Jefferson City
Jefferson City is located in United States.
| GPS Coordinates (DMS) | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
|---|---|
| Latitude | 38.57670 |
| Longitude | -92.17352 |
| Altitude | 195 m |
| Country | United States |
Jefferson City Distances to Cities
| Jefferson City | Distance |
|---|---|
| Distance from Jefferson City to Sacramento | 2,544 km |
| Distance from Jefferson City to Boston | 1,834 km |
| Distance from Jefferson City to San Francisco | 2,640 km |
| Distance from Jefferson City to Los Angeles | 2,386 km |
| Distance from Jefferson City to Dallas | 767 km |
Seven Oaks
Seven Oaks is located in United States.
| GPS Coordinates | 34° 2´ 55.5360'' N 81° 8´ 47.3280'' W |
|---|---|
| Latitude | 34.04876 |
| Longitude | -81.14648 |
| Altitude | 73 m |
| Country | United States |
Seven Oaks Distances to Cities
| Seven Oaks | Distance |
|---|---|
| Distance from Seven Oaks to Naugatuck | 1,090 km |
| Distance from Seven Oaks to Austin Tx | 1,619 km |
| Distance from Seven Oaks to Farragut | 342 km |
| Distance from Seven Oaks to Knoxville | 330 km |
| Distance from Seven Oaks to Albertville | 467 km |