Distance from Jefferson City to Sandy City
Distance from Jefferson City to Sandy City is 1,704 kilometers. This air travel distance is equal to 1,059 miles.
The air travel (bird fly) shortest distance between Jefferson City and Sandy City is 1,704 km= 1,059 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jefferson City to Sandy City, It takes 1.89 hours to arrive.
Jefferson City
Jefferson City is located in United States.
| GPS Coordinates (DMS) | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
|---|---|
| Latitude | 38.57670 |
| Longitude | -92.17352 |
| Altitude | 195 m |
| Country | United States |
Jefferson City Distances to Cities
| Jefferson City | Distance |
|---|---|
| Distance from Jefferson City to Sacramento | 2,544 km |
| Distance from Jefferson City to Boston | 1,834 km |
| Distance from Jefferson City to San Francisco | 2,640 km |
| Distance from Jefferson City to Los Angeles | 2,386 km |
| Distance from Jefferson City to Dallas | 767 km |
Sandy City
Sandy City is located in United States.
| GPS Coordinates | 40° 35´ 29.7960'' N 111° 53´ 2.7600'' W |
|---|---|
| Latitude | 40.59161 |
| Longitude | -111.88410 |
| Altitude | 1348 m |
| Country | United States |
Sandy City Distances to Cities
| Sandy City | Distance |
|---|---|
| Distance from Sandy City to Pullman | 804 km |
| Distance from Sandy City to Centralia | 1,121 km |
| Distance from Sandy City to Pearl City Manana | 4,820 km |
| Distance from Sandy City to South Hill | 1,106 km |
| Distance from Sandy City to Vineyard | 847 km |