Distance from Jefferson City to Sand Springs
Distance from Jefferson City to Sand Springs is 441 kilometers. This air travel distance is equal to 274 miles.
The air travel (bird fly) shortest distance between Jefferson City and Sand Springs is 441 km= 274 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jefferson City to Sand Springs, It takes 0.49 hours to arrive.
Jefferson City
Jefferson City is located in United States.
| GPS Coordinates (DMS) | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
|---|---|
| Latitude | 38.57670 |
| Longitude | -92.17352 |
| Altitude | 195 m |
| Country | United States |
Jefferson City Distances to Cities
| Jefferson City | Distance |
|---|---|
| Distance from Jefferson City to Sacramento | 2,544 km |
| Distance from Jefferson City to Boston | 1,834 km |
| Distance from Jefferson City to San Francisco | 2,640 km |
| Distance from Jefferson City to Los Angeles | 2,386 km |
| Distance from Jefferson City to Dallas | 767 km |
Sand Springs
Sand Springs is located in United States.
| GPS Coordinates | 36° 8´ 23.3160'' N 96° 6´ 32.0040'' W |
|---|---|
| Latitude | 36.13981 |
| Longitude | -96.10889 |
| Altitude | 212 m |
| Country | United States |
Sand Springs Distances to Cities
| Sand Springs | Distance |
|---|---|
| Distance from Sand Springs to Tahlequah | 106 km |
| Distance from Sand Springs to Amarillo | 528 km |
| Distance from Sand Springs to Sapulpa | 16 km |
| Distance from Sand Springs to Wasco Ca | 2,094 km |
| Distance from Sand Springs to Tulsa | 11 km |