Distance from Jefferson City to San Angelo
Distance from Jefferson City to San Angelo is 1,091 kilometers. This air travel distance is equal to 678 miles.
The air travel (bird fly) shortest distance between Jefferson City and San Angelo is 1,091 km= 678 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jefferson City to San Angelo, It takes 1.21 hours to arrive.
Jefferson City
Jefferson City is located in United States.
GPS Coordinates (DMS) | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
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Latitude | 38.57670 |
Longitude | -92.17352 |
Altitude | 195 m |
Country | United States |
Jefferson City Distances to Cities
Jefferson City | Distance |
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Distance from Jefferson City to Sacramento | 2,544 km |
Distance from Jefferson City to Boston | 1,834 km |
Distance from Jefferson City to San Francisco | 2,640 km |
Distance from Jefferson City to Los Angeles | 2,386 km |
Distance from Jefferson City to Dallas | 767 km |
San Angelo
San Angelo is located in United States.
GPS Coordinates | 31° 27´ 49.5720'' N 100° 26´ 13.3440'' W |
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Latitude | 31.46377 |
Longitude | -100.43704 |
Altitude | 564 m |
Country | United States |
San Angelo Distances to Cities
San Angelo | Distance |
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Distance from San Angelo to Eagle | 1,948 km |
Distance from San Angelo to West Odessa | 200 km |
Distance from San Angelo to Moscow | 2,210 km |
Distance from San Angelo to Twin Falls | 1,749 km |
Distance from San Angelo to Albany Or | 2,455 km |