Distance from Jefferson City to Prospect Heights
Distance from Jefferson City to Prospect Heights is 531 kilometers. This air travel distance is equal to 330 miles.
The air travel (bird fly) shortest distance between Jefferson City and Prospect Heights is 531 km= 330 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jefferson City to Prospect Heights, It takes 0.59 hours to arrive.
Jefferson City
Jefferson City is located in United States.
| GPS Coordinates (DMS) | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
|---|---|
| Latitude | 38.57670 |
| Longitude | -92.17352 |
| Altitude | 195 m |
| Country | United States |
Jefferson City Distances to Cities
| Jefferson City | Distance |
|---|---|
| Distance from Jefferson City to Sacramento | 2,544 km |
| Distance from Jefferson City to Boston | 1,834 km |
| Distance from Jefferson City to San Francisco | 2,640 km |
| Distance from Jefferson City to Los Angeles | 2,386 km |
| Distance from Jefferson City to Dallas | 767 km |
Prospect Heights
Prospect Heights is located in United States.
| GPS Coordinates | 42° 5´ 43.0800'' N 87° 56´ 15.2520'' W |
|---|---|
| Latitude | 42.09530 |
| Longitude | -87.93757 |
| Altitude | 207 m |
| Country | United States |
Prospect Heights Distances to Cities
| Prospect Heights | Distance |
|---|---|
| Distance from Prospect Heights to Albany Ny | 1,168 km |
| Distance from Prospect Heights to Albert Lea | 476 km |
| Distance from Prospect Heights to Fridley | 543 km |
| Distance from Prospect Heights to North Olmsted | 506 km |
| Distance from Prospect Heights to Owosso | 325 km |