Distance from Jefferson City to Farragut
Distance from Jefferson City to Farragut is 772 kilometers. This air travel distance is equal to 480 miles.
The air travel (bird fly) shortest distance between Jefferson City and Farragut is 772 km= 480 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jefferson City to Farragut, It takes 0.86 hours to arrive.
Jefferson City
Jefferson City is located in United States.
GPS Coordinates (DMS) | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
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Latitude | 38.57670 |
Longitude | -92.17352 |
Altitude | 195 m |
Country | United States |
Jefferson City Distances to Cities
Jefferson City | Distance |
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Distance from Jefferson City to Sacramento | 2,544 km |
Distance from Jefferson City to Boston | 1,834 km |
Distance from Jefferson City to San Francisco | 2,640 km |
Distance from Jefferson City to Los Angeles | 2,386 km |
Distance from Jefferson City to Dallas | 767 km |
Farragut
Farragut is located in United States.
GPS Coordinates | 35° 53´ 4.2720'' N 84° 9´ 12.7080'' W |
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Latitude | 35.88452 |
Longitude | -84.15353 |
Altitude | 266 m |
Country | United States |
Farragut Distances to Cities
Farragut | Distance |
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Distance from Farragut to Lynchburg | 479 km |
Distance from Farragut to Memphis | 541 km |
Distance from Farragut to Mount Juliet | 216 km |
Distance from Farragut to Hayesville | 3,410 km |
Distance from Farragut to Burke | 690 km |