Distance from Jefferson City to East Patchogue
Distance from Jefferson City to East Patchogue is 1,660 kilometers. This air travel distance is equal to 1,031 miles.
The air travel (bird fly) shortest distance between Jefferson City and East Patchogue is 1,660 km= 1,031 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jefferson City to East Patchogue, It takes 1.84 hours to arrive.
Jefferson City
Jefferson City is located in United States.
| GPS Coordinates (DMS) | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
|---|---|
| Latitude | 38.57670 |
| Longitude | -92.17352 |
| Altitude | 195 m |
| Country | United States |
Jefferson City Distances to Cities
| Jefferson City | Distance |
|---|---|
| Distance from Jefferson City to Sacramento | 2,544 km |
| Distance from Jefferson City to Boston | 1,834 km |
| Distance from Jefferson City to San Francisco | 2,640 km |
| Distance from Jefferson City to Los Angeles | 2,386 km |
| Distance from Jefferson City to Dallas | 767 km |
East Patchogue
East Patchogue is located in United States.
| GPS Coordinates | 40° 46´ 1.3440'' N 72° 59´ 46.3920'' W |
|---|---|
| Latitude | 40.76704 |
| Longitude | -72.99622 |
| Altitude | 9 m |
| Country | United States |