Distance from Jefferson City to Buckeye
Distance from Jefferson City to Buckeye is 1,925 kilometers. This air travel distance is equal to 1,196 miles.
The air travel (bird fly) shortest distance between Jefferson City and Buckeye is 1,925 km= 1,196 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jefferson City to Buckeye, It takes 2.14 hours to arrive.
Jefferson City
Jefferson City is located in United States.
GPS Coordinates (DMS) | 38° 34´ 36.1200'' N 92° 10´ 24.6720'' W |
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Latitude | 38.57670 |
Longitude | -92.17352 |
Altitude | 195 m |
Country | United States |
Jefferson City Distances to Cities
Jefferson City | Distance |
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Distance from Jefferson City to Sacramento | 2,544 km |
Distance from Jefferson City to Boston | 1,834 km |
Distance from Jefferson City to San Francisco | 2,640 km |
Distance from Jefferson City to Los Angeles | 2,386 km |
Distance from Jefferson City to Dallas | 767 km |
Buckeye
Buckeye is located in United States.
GPS Coordinates | 33° 22´ 13.1520'' N 112° 35´ 1.6080'' W |
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Latitude | 33.37032 |
Longitude | -112.58378 |
Altitude | 264 m |
Country | United States |
Buckeye Distances to Cities
Buckeye | Distance |
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Distance from Buckeye to Chandler | 69 km |
Distance from Buckeye to Phoenix | 48 km |
Distance from Buckeye to Duarte | 507 km |
Distance from Buckeye to Claremont | 483 km |
Distance from Buckeye to Sierra Vista | 294 km |