Distance from Jacksonville to Sacramento
Distance from Jacksonville to Sacramento is 2,692 kilometers. This air travel distance is equal to 1,673 miles.
The air travel (bird fly) shortest distance between Jacksonville and Sacramento is 2,692 km= 1,673 miles.
If you travel with an airplane (which has average speed of 560 miles) from Jacksonville to Sacramento, It takes 2.99 hours to arrive.
Jacksonville
Jacksonville is located in United States.
| GPS Coordinates (DMS) | 39° 44´ 2.1840'' N 90° 13´ 44.4360'' W |
|---|---|
| Latitude | 39.73394 |
| Longitude | -90.22901 |
| Altitude | 190 m |
| Country | United States |
Jacksonville Distances to Cities
Sacramento
Sacramento is located in United States.
| GPS Coordinates | 38° 34´ 53.6520'' N 121° 29´ 39.8400'' W |
|---|---|
| Latitude | 38.58157 |
| Longitude | -121.49440 |
| Altitude | 14 m |
| Country | United States |