Distance from Gambat to Aleksandrovskoye
Distance from Gambat to Aleksandrovskoye is 2,978 kilometers. This air travel distance is equal to 1,850 miles.
The air travel (bird fly) shortest distance between Gambat and Aleksandrovskoye is 2,978 km= 1,850 miles.
If you travel with an airplane (which has average speed of 560 miles) from Gambat to Aleksandrovskoye, It takes 3.3 hours to arrive.
Gambat
Gambat is located in Pakistan.
| GPS Coordinates (DMS) | 27° 21´ 5.2200'' N 68° 31´ 13.8360'' E |
|---|---|
| Latitude | 27.35145 |
| Longitude | 68.52051 |
| Altitude | 57 m |
| Country | Pakistan |
Gambat Distances to Cities
| Gambat | Distance |
|---|---|
| Distance from Gambat to Aleksandrovskoye | 2,978 km |
| Distance from Gambat to Bryansk | 4,017 km |
| Distance from Gambat to Gryazovets | 4,125 km |
| Distance from Gambat to Labinsk | 3,129 km |
| Distance from Gambat to Temryuk | 3,396 km |
Aleksandrovskoye
Aleksandrovskoye is located in Russia.
| GPS Coordinates | 44° 42´ 51.0120'' N 43° 0´ 2.9880'' E |
|---|---|
| Latitude | 44.71417 |
| Longitude | 43.00083 |
| Altitude | 295 m |
| Country | Russia |