Distance from to

Distance from Florida to Seymour

Distance from Florida to Seymour is 1,707 kilometers. This air travel distance is equal to 1,061 miles.

The air travel (bird fly) shortest distance between Florida and Seymour is 1,707 km= 1,061 miles.

If you travel with an airplane (which has average speed of 560 miles) from Florida to Seymour, It takes 1.89 hours to arrive.

Florida

Florida is located in United States.

GPS Coordinates (DMS)27° 39´ 53.3880'' N
81° 30´ 56.7000'' W
Latitude27.66483
Longitude-81.51575
Altitude29 m
CountryUnited States

Florida Distances to Cities

FloridaDistance
Distance from Florida to California3,687 km
Distance from Florida to New York1,603 km
Distance from Florida to Texas1,838 km
Distance from Florida to Georgia516 km
Distance from Florida to New Jersey1,523 km

Seymour

Seymour is located in United States.

GPS Coordinates41° 23´ 48.3360'' N
73° 4´ 33.3840'' W
Latitude41.39676
Longitude-73.07594
Altitude30 m
CountryUnited States

Seymour Distances to Cities

SeymourDistance
Distance from Seymour Ct to Torrance4,036 km
Distance from Seymour Ct to Orange Ca3,998 km
Distance from Seymour Ct to Cambridge196 km
Distance from Seymour Ct to Albany Ca4,186 km
Distance from Seymour Ct to Bedford Nh215 km

Map of Florida

Map of Seymour